Source code viewer in HTML
384
Devendraoli
9 авг 2014 г., 9:18
Guys i have written a script for viewing website html code and it was working normal when i created but not working when i slightly modify it, pleases fix if you can
Onatolich
10 авг 2014 г., 1:07
If I understand right, you need something like this:
$source = $_POST['source'];
if(preg_match('#http:\/\/(.*)#ui'))
echo htmlspecialchars(file_get_contents($source));
$source = $_POST['source'];
if(preg_match('#http:\/\/(.*)#ui'))
echo htmlspecialchars(file_get_contents($source));
Koenig
11 авг 2014 г., 23:33
(\/)____o_O____(\/)
# Onatolich (10.08.2014 / 01:07)you can use nl2br()
If I understand right, you need something like this:
$source = $_POST['source'];
if(preg_match('#http:\/\/(.*)#ui'))
echo htmlspecialchars(file_get_contents($source));
Всего: 4
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