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help me !
3-stroka

$g = mysql_result(mysql_query("SELECT COUNT (*) FROM `my_guests` WHERE `my_id` = '" . $user['id'] . "' AND `guest_id` = '" . $user_id . "';"), 0);

не зацепился

Krite (13.02.2011/12:48)

быдло ошибка
замени
$g = mysql_result(mysql_query("SELECT * FROM `my_guests` WHERE `my_id` = '" . $user['id'] . "' AND `guest_id` = '" . $user_id . "' LIMIT 1;"), 0);
на
$g = mysql_result(m

help me, error like this

пример