Просмотр поста

хочу вывести в анкету где находится юзер...

$onltime = $realtime - 300;
$total = mysql_result(mysql_query("SELECT COUNT(*) FROM `" . ($act == 'guest' ? 'cms_guests' : 'users') . "` WHERE `lastdate` > '$onltime'"), 0);
if ($total) {
    $req = mysql_query("SELECT * FROM `" . ($act == 'guest' ? 'cms_guests' : 'users') . "` WHERE `lastdate` > '$onltime' ORDER BY " . ($act == 'guest' ? "`movings` DESC" : "`name` ASC") . " LIMIT $start,$kmess");
    while ($res = mysql_fetch_assoc($req)) {
        $place = explode(':||||:', $res['placet']);
        $place[1] = $place[1] ? $place[1] : $place[0];
        $place = '<a href="'.$place[0].'">'.$place[1].'</a>';
}
///вывод
echo '<li><span class="gray">Сейчас: ';
if ($realtime > $user['lastdate'] + 300) {
echo '<span class="red"> [ В реале ]</span>';
$lastvisit = date("d.m.Y (H:i)", $user['lastdate']);
} else {
echo '<span class="green">'.$place.'</span>';
}
echo '</span></li>';
}